 | Charles Vyse - 1785 - 350 pagine
...its Diameter is 8000 Miles ? PROBLEM VII. To find the Area of a Circle. RULES. 1 . Multiply Half the the Circumference by Half the Diameter, and the Product will be the Area. Or, 2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area. Or, • 3.... | |
 | Benjamin Donne - 1796 - 120 pagine
...circumfcribing prifm; therefore, meafure it as a cylinder, and take two thirds of the product, viz. multiply half the circumference by half the diameter, and the product will be the area of the bafe of the cylinder, which multiplied by the length (height) of the cylinder (which is equal... | |
 | Peter Nicholson - 1809 - 426 pagine
...the greater segment. PROBLEM XVI. To find the area of a circle, the diameter being given. METHOD I. Multiply half the circumference by half the diameter, and the product will be the area. i EXAMPLE I. What u the area nf a circle lahose diameter is 28 feet, and its circumference 88 feet?... | |
 | Charles Vyse - 1815 - 340 pagine
...perfectly round, and its diameter be 8000 miles? PROBLEM' VIL To find the area of a circle. RULES. ' 1. Multiply half the circumference by half the diameter, and the product will he the area. Or, 2. Multiply the square of the diameter by ,7854, and the product will be the area.... | |
 | William Jillard Hort - 1822 - 308 pagine
...opposite angle, and half the product will be the area. Problem. To find the area of a circle. Rule 1. Multiply half the circumference by half the diameter, and the product will be the area. Rule 2. Multiply the square of the diameter by 7854', and the product will be the area. ProUem. To find... | |
 | Jacob Willetts - 1822 - 200 pagine
...circumference to the diameter ; Or; as 3. 1416 is to 1, so is the circumference to the diameter. III. .Multiply half the circumference by half the diameter and the product will be the area. Or multiply the square of the diameter by. 7854, and the pro* duct will be the area. Or multiply the... | |
 | Anthony Nesbit - 1824 - 476 pagine
...may consult Marrat's Mechanics. Article 768. PROBLEM XV. To find the area of a circle. RULES. _ , 1. Multiply half the circumference by half the diameter, and the product will be the area. Or, divide the product of the whole circumference and diameter by 4t9 and the quotient will be the... | |
 | Peter Nicholson - 1825 - 1046 pagine
...of the greater segment. Prob. 1 6. To find the area of a circle, the diameter being given. Method 1. Multiply half the circumference by half the diameter, and the product will be the area. Ex. l. What is the area of a circle whose diameter is 28 feet, and iU circumference 88 feet ? Method... | |
 | Zadock Thompson - 1826 - 176 pagine
...miles, what is its diameter ? Ans. 79571 nearly. Problem VI. To find the area of a circkj RULE. — Multiply half the circumference by half the diameter, and . the product will be the area. * These three methods do not exactly agree, but the last is the most correct. The exact proportion... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 pagine
...radius of its inscribed circle, (or perpendicular demitted from the centre upon one of them,) and half the product will be the area. RULE II. Multiply the square of a side, by the multiplier standing opposite its name in the following table, and the product will be... | |
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Multiply half the circumference by half the diameter, and the product will be the area. Or, divide the product of the whole circumference and diameter -by 4, and the quotient will be the area. 2. Multiply the square of the diameter by .7854, and the product... 
