Elements of Geometry, Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids: To which are Added, Elements of Plane and Spherical TrignonometryBell & Bradfute, 1875 - 257 pagine |
Dall'interno del libro
Risultati 1-5 di 58
Pagina 8
... DF ; wherefore likewise , the angle BAC coincides with the angle EDF , and is equal ( Ax . 8 ) to it . Therefore , if two triangles , & c . Q. E. D. See Note to Prop . IV . PROP . IX . PROB . To bisect a given 8 ELEMENTS OF GEOMETRY .
... DF ; wherefore likewise , the angle BAC coincides with the angle EDF , and is equal ( Ax . 8 ) to it . Therefore , if two triangles , & c . Q. E. D. See Note to Prop . IV . PROP . IX . PROB . To bisect a given 8 ELEMENTS OF GEOMETRY .
Pagina 9
... bisected by the straight B line AF . Which was to be done . PROP . X. PROB . DA F E To bisect a given finite straight line ; that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it ...
... bisected by the straight B line AF . Which was to be done . PROP . X. PROB . DA F E To bisect a given finite straight line ; that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it ...
Pagina 10
... bisect ( I. 10 ) FG in H , and join CF , CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . D Because FH is equal to HG , and HC is common to the two triangles FHC , GHC ...
... bisect ( I. 10 ) FG in H , and join CF , CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . D Because FH is equal to HG , and HC is common to the two triangles FHC , GHC ...
Pagina 12
... Bisect ( I. 10 ) AC in E , join BE and produce it to F , and make EF equal to BE ; join also FC , and produce AC to ... bisected , it may be demonstrated that the angle BCG , that is , ( I. 15 ) the angle ACD , is greater than the angle ...
... Bisect ( I. 10 ) AC in E , join BE and produce it to F , and make EF equal to BE ; join also FC , and produce AC to ... bisected , it may be demonstrated that the angle BCG , that is , ( I. 15 ) the angle ACD , is greater than the angle ...
Pagina 26
... Bisect ( I. 10 ) BC in E , join AE , and at the point E in the straight line EC make ( I. 23 ) the angle CEF equal to D ; and through A draw ( I. 31 ) AG parallel to BC , and through C draw CG ( I. 31 ) parallel to EF ; therefore FECG ...
... Bisect ( I. 10 ) BC in E , join AE , and at the point E in the straight line EC make ( I. 23 ) the angle CEF equal to D ; and through A draw ( I. 31 ) AG parallel to BC , and through C draw CG ( I. 31 ) parallel to EF ; therefore FECG ...
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Elements of Geometry; Containing the First Six Books of Euclid, With Two ... John 1748-1819 Playfair Anteprima non disponibile - 2021 |
Parole e frasi comuni
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter draw equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore given circle given point given straight line hypotenuse inscribed less Let ABC Let the straight meet multiple opposite angle parallel parallelogram perpendicular plane polygon prism PROB produced proportionals proposition Q. E. D. COR Q. E. D. PROP radius rectangle contained rectilineal figure remaining angle right angles segment semicircle similar sine solid angle solid parallelepipeds spherical angle spherical triangle straight line AC straight line drawn tangent THEOR third three straight lines touches the circle triangle ABC triangle DEF wherefore