Analytical Chemistry: An IntroductionSaunders College Pub., 1994 - 675 pagine |
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Risultati 1-3 di 61
Pagina 172
... NaOH , mL with 0.1000 M NaOH with 0.001000 M NaOH 0.00 1.30 3.30 10.00 1.60 3.60 20.00 2.15 4.15 24.00 2.87 4.87 24.90 3.87 5.87 25.00 7.00 7.00 25.10 10.12 8.12 26.00 11.12 9.12 30.00 11.80 9.80 Equivalence point At the equivalence ...
... NaOH , mL with 0.1000 M NaOH with 0.001000 M NaOH 0.00 1.30 3.30 10.00 1.60 3.60 20.00 2.15 4.15 24.00 2.87 4.87 24.90 3.87 5.87 25.00 7.00 7.00 25.10 10.12 8.12 26.00 11.12 9.12 30.00 11.80 9.80 Equivalence point At the equivalence ...
Pagina 211
... NaOH and 0.0300 M in Na2S . ( d ) 0.0100 M in NaOH and 0.0300 M in sodium acetate . * 11-16 . Identify the principal conjugate acid / base pair and calcu- late the ratio between them in a solution that is buffered to pH 6.00 and ...
... NaOH and 0.0300 M in Na2S . ( d ) 0.0100 M in NaOH and 0.0300 M in sodium acetate . * 11-16 . Identify the principal conjugate acid / base pair and calcu- late the ratio between them in a solution that is buffered to pH 6.00 and ...
Pagina 225
... NaOH : · ( NH4 ) 3 12M0O3 ( s ) + 260H ̄ → HPO2 + 12MoO2 + 14H2O + 3NH3 ( g ) After the solution was boiled to remove the NH3 , the excess NaOH was titrated with 14.17 mL of 0.1741 M HCl to a phenolphthalein end point . Calculate the ...
... NaOH : · ( NH4 ) 3 12M0O3 ( s ) + 260H ̄ → HPO2 + 12MoO2 + 14H2O + 3NH3 ( g ) After the solution was boiled to remove the NH3 , the excess NaOH was titrated with 14.17 mL of 0.1741 M HCl to a phenolphthalein end point . Calculate the ...
Parole e frasi comuni
absorbance absorption acid activity added addition amount analysis analyte applications approximately atomic base becomes buffer Calculate carbonate cations cause cell charge chemical chloride chromatography color column complex compounds concentration consider constant containing curve described determination difference dilute dissociation dissolved EDTA effect electrode electrode potential electrolyte end point Equation equilibrium equivalence error example excess expression Figure filter formation give given glass H₂O H3O+ hydrogen hydroxide increase indicator involves less liquid mass mean measurements metal method mmol molar NaOH needed Note obtained occurs organic oxidation particles positive potassium potential precipitate prepared quantity radiation range reaction reagent reduced reference relative salt sample shown shows silver sodium solid solubility solution species standard standard deviation strong surface Table temperature tion titration types volume weighed write