 | Charles Davies - 1854 - 436 pagine
...consequently, the two equiangular triangles BAC, CED, are similar figures. Cor. Two triangles which have two angles of the one equal to two angles of the other, are similar ; for, the third angles are then equal, and the two triangles are equian gular (BI, p.... | |
 | Euclides - 1855 - 270 pagine
...EDF. Therefore, if two triangles, &c. QED The enunciation of this proposition may be thus simplif'ed: If two triangles have two angles of the one, equal to two angles of the other, each to each, and a side of the one equal to a side of the other similarly situated as to the equal angles, the two triangles... | |
 | Euclides - 1855 - 230 pagine
...the angle EBC (4): and the angle AEG is equal to the angle BEH (a); therefore the triangles AEG, BEH have two angles of the one, equal to two angles of the other, each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another; wherefore they have their other... | |
 | Robert Potts - 1855 - 1050 pagine
...drawn to intersect one another, the greater segments will be equal to the sides of the pentagon. 3. If two triangles have two angles of the one equal to two angles of the other, and one side equal to one side, viz. either the sides adjacent to the equal angles in each, or the... | |
 | John Playfair - 1855 - 334 pagine
...it is not equal to it: therefore the angle BAC is greater than the angle EDF. PROP. XXVI. THLOR. Jf two triangles have two angles of the one equal to two angles of the otIirr, each to each; and one side equal to one side, viz. either the sides adjacent to the equal anglrs,... | |
 | Cambridge univ, exam. papers - 1856 - 200 pagine
...on the same side of it, are either two right angles, or are together equal to two right angles. 3. If two triangles have two angles of the one equal to two angles of the other, each to each, and one si ie equal to one side, via. the sides opposite to equal angles in each, then shall the other sides... | |
 | Peter Nicholson - 1856 - 518 pagine
...parallel to CD, the alternate angles, GFE, FGH, are also equal ; therefore the two triangles GEF, HFG, have two angles of the one equal to two angles of the other, each to each ; and the side FG, adjacent to the equal angles, common ; the triangles are therefore equal (theorem 6) ;... | |
 | Euclides - 1856 - 168 pagine
...BAC, and the angle ABE is equal to the angle ABC (being both right angles), the triangles ABC, ABE have two angles of the one equal to two angles of the other, and the side AB common to the two. Therefore the triangles ABC, ABE are equal, and the side AE is equal... | |
 | Elias Loomis - 1857 - 242 pagine
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG have two angles of the one equal to two angles of the other, each to each, and the side Eli included between the equal angles, common ; hence the triangles are equal (Prop. VII.)... | |
 | William Ernest Johnson - 1889 - 574 pagine
...draw IX, IT, IZ perpendiculars on the sides. Then, the triangles BXI, BZ1 having a common side BI and two angles of the one equal to two angles of the other, are equal in all respects, so that IX=IZ. Similarly IX=IY, :.IY=IZ. Therefore, the triangles AZI, A... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal... 
