 | Edward Atkins - 1876 - 130 pagine
...t DAF = /EAF. the straight line AF. Proposition 10. — Problem. To bisect a given Jinite straight line, that is, to divide it into two equal parts. Let AB lie the given straight line. It is required to divide it into two equal parts. CONSTRUCTION. — Upon... | |
 | Euclides - 1877 - 58 pagine
...shall be equidistant from its angular points. PROPOSITION X. PROBLEM. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line ; it w required to bisect it. Construction. Upon AB describe an equilateral triangle... | |
 | Edward Atkins - 1877 - 72 pagine
...bisected by the straight line AF. QEF Proposition 10. — Problem. To bisect a givsn finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line. It is required to divide it into two equal parts CONSTRUCTION. — Upon AB describe... | |
 | Euclides - 1879 - 146 pagine
...be divided into 4, 8, 16 &c. equal /. s.] PROPOSITION X. PROBLEM. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given finite st. line. It is required to divide AB into two equal parts. Constr. On AB describe the equilat. A ABC... | |
 | Moffatt and Paige - 1879 - 428 pagine
...Therefore the angle BAC is bisected by A F. QEF Proposition X. Problem. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line, It is required to bisect it. On AB describe the equilateral triangle ABC (I. l). Bisect... | |
 | Isaac Todhunter - 1880 - 426 pagine
...is bisected by the straight line AF. QEF PROPOSITION 10. PROBLEM. To bisect a given finite straight line, that is to divide it into two equal parts. Let AB be the given straight line : it is required to divide it into two equal parts. Describe on it an equilateral triangle... | |
 | Euclides, Frederick Burn Harvey - 1880 - 178 pagine
...prove that A ^ bisects the angle CBE. PROP. X. PROBLEM. To bisect a given finite straight line, ie to divide it into two equal parts. Let AB be the given finite straight line : It is required to bisect it. CONSTRUCTION. — 1. On AB construct an equilateral triangle... | |
 | Euclides - 1881 - 236 pagine
...to each ; and the base DF is equal (Const.) to the baseEF. Therefore the angle DAF is equal (I. S) to the angle EAF. Wherefore the given rectilineal angle BAC is bisected by the straight line A FQ E, F. By meana of this proposition, an angle may be divided iuto any number of equal... | |
 | Euclid, Isaac Todhunter - 1883 - 428 pagine
...is bisected by the straight line AF. QEF PROPOSITION 10. PROBLEM. To bisect a given finite straight line, that is to divide it into two equal parts. Let AB be the given straight line : it is required to divide it into two equal parts. Describe on it an equilateral triangle... | |
 | Edward Mann Langley, W. Seys Phillips - 1890 - 538 pagine
...figure, and AF is called its axis of symmetry. PROPOSITION 10. PROBLEM. To bisect a given finite straight line — that is, to divide it into two equal parts. Let AB be the given straight line; it is required to divide it into two equal parts. Describe on AB an equilateral A ABC.... | |
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To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts. 
